# LeetCode – Implement Stack using Queues
Date: 2019-10-07


### **题目：**

Implement the following operations of a stack using queues.

- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.

**Example:**

```
MyStack stack = new MyStack();

stack.push(1);
stack.push(2);  
stack.top();   // returns 2
stack.pop();   // returns 2
stack.empty(); // returns false
```

**Notes:**

- You must use _only_ standard operations of a queue -- which means only `push to back`, `peek/pop from front`, `size`, and `is empty` operations are valid.
- Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

### **解题：**

本地使用queue实现一个stack的功能， queue特点是先进先出， stack的特点是先进后出

1. 调整push部分：每加入新元素x时，把queue中现存的元素从队列头（front）元素取出放入放入队列（队列的rear），这样pop和top时顺序与stack一致，先进后出， 其他三个操作也就直接调用queue的操作即可，参见代码如下：                  

### **实现：**

```
class MyStack {
private:
    queue<int> q;
        
public:
    /** Initialize your data structure here. */
    MyStack() {
        
    }
    
    /** Push element x onto stack. */
    void push(int x) {
        q.push(x);
        for (int i=0; i<q.size()-1;i++){
            q.push(q.front());
            q.pop();
        }
                
    }
    
    /** Removes the element on top of the stack and returns that element. */
    int pop() {
        int x = q.front();
        q.pop();
        return x;
    }
    
    /** Get the top element. */
    int top() {
        return q.front();
    }
    
    /** Returns whether the stack is empty. */
    bool empty() {
        return q.empty();
    }
};
```

### **解题：**

        本地使用queue实现一个stack的功能， queue特点是先进先出， stack的特点是先进后出

1. 调整pop或top部分： 把queue中现存的元素从队列头（front）元素取出放入放入队列（队列的rear），循环size-1次， top操作获取后恢复原有顺序， pop操作直接出队列， push操作也就直接调用queue的操作即可，参见代码如下：

```

class MyStack {
private:
    queue<int> q ;
        
public:
    /** Initialize your data structure here. */
    MyStack() {
        
    }
    
    /** Push element x onto stack. */
    void push(int x) {
        q.push(x);              
    }
    
    /** Removes the element on top of the stack and returns that element. */
    int pop() {
        int x;
        for (int i=0; i<q.size()-1;i++){
            q.push(q.front());
            q.pop();
        }
        x = q.front();
        q.pop();
        return x;
    }
    
    /** Get the top element. */
    int top() {
        int x;
        for (int i=0; i<q.size()-1;i++){
            q.push(q.front());
            q.pop();
        }
        x = q.front();
        
        q.push(q.front());
        q.pop();
        return x;
    }
    
    /** Returns whether the stack is empty. */
    bool empty() {
        return q.empty();
    }
};
```