# LeetCode – Implement Stack using Queues

### 题目：

Implement the following operations of a stack using queues.

• push(x) — Push element x onto stack.
• pop() — Removes the element on top of the stack.
• top() — Get the top element.
• empty() — Return whether the stack is empty.

Example:

```MyStack stack = new MyStack();

stack.push(1);
stack.push(2);
stack.top();   // returns 2
stack.pop();   // returns 2
stack.empty(); // returns false```

Notes:

• You must use only standard operations of a queue — which means only `push to back``peek/pop from front``size`, and `is empty` operations are valid.
• Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
• You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

### 解题：

1. 调整push部分：每加入新元素x时，把queue中现存的元素从队列头（front）元素取出放入放入队列（队列的rear），这样pop和top时顺序与stack一致，先进后出， 其他三个操作也就直接调用queue的操作即可，参见代码如下：

### 实现：

``````class MyStack {
private:
queue<int> q;

public:
/** Initialize your data structure here. */
MyStack() {

}

/** Push element x onto stack. */
void push(int x) {
q.push(x);
for (int i=0; i<q.size()-1;i++){
q.push(q.front());
q.pop();
}

}

/** Removes the element on top of the stack and returns that element. */
int pop() {
int x = q.front();
q.pop();
return x;
}

/** Get the top element. */
int top() {
return q.front();
}

/** Returns whether the stack is empty. */
bool empty() {
return q.empty();
}
};
``````

### 解题：

本地使用queue实现一个stack的功能， queue特点是先进先出， stack的特点是先进后出

1. 调整pop或top部分： 把queue中现存的元素从队列头（front）元素取出放入放入队列（队列的rear），循环size-1次， top操作获取后恢复原有顺序， pop操作直接出队列， push操作也就直接调用queue的操作即可，参见代码如下：
``````
class MyStack {
private:
queue<int> q ;

public:
/** Initialize your data structure here. */
MyStack() {

}

/** Push element x onto stack. */
void push(int x) {
q.push(x);
}

/** Removes the element on top of the stack and returns that element. */
int pop() {
int x;
for (int i=0; i<q.size()-1;i++){
q.push(q.front());
q.pop();
}
x = q.front();
q.pop();
return x;
}

/** Get the top element. */
int top() {
int x;
for (int i=0; i<q.size()-1;i++){
q.push(q.front());
q.pop();
}
x = q.front();

q.push(q.front());
q.pop();
return x;
}

/** Returns whether the stack is empty. */
bool empty() {
return q.empty();
}
};``````