题目:
Implement the following operations of a queue using stacks.
- push(x) — Push element x to the back of queue.
- pop() — Removes the element from in front of queue.
- peek() — Get the front element.
- empty() — Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue(); queue.push(1); queue.push(2); queue.peek(); // returns 1 queue.pop(); // returns 1 queue.empty(); // returns false
Notes:
- You must use only standard operations of a stack — which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
解题:
本地使用stack实现一个queue的功能, queue特点是先进先出, stack的特点是先进后出
- 创建一个辅助栈tmp,把s的元素也逆着顺序存入tmp中,此时加入新元素x,再把tmp中的元素取出放入input,其他三个操作也就直接调用栈的操作即可,参见代码如下:
实现:
class MyQueue {
private:
stack<int> input,output;
public:
/** Initialize your data structure here. */
MyQueue() {
}
/** Push element x to the back of queue. */
void push(int x) {
stack<int> tmp;
while (!input.empty()){
tmp.push(input.top());
input.pop();
}
input.push(x);
while(!tmp.empty()){
input.push(tmp.top());
tmp.pop();
}
}
/** Removes the element from in front of queue and returns that element. */
int pop() {
int val;
val = input.top();
input.pop();
return val;
}
/** Get the front element. */
int peek() {
return input.top();
}
/** Returns whether the queue is empty. */
bool empty() {
return input.empty();
}
解题:
2 .入栈不处理, 出栈的时候,通过临时栈进行转换
class MyQueue {
private:
stack<int> input,output;
public:
/** Initialize your data structure here. */
MyQueue() {
}
/** Push element x to the back of queue. */
void push(int x) {
input.push(x);
}
/** Removes the element from in front of queue and returns that element. */
int pop() {
peek();
int val;
val = output.top();
output.pop();
return val;
}
/** Get the front element. */
int peek() {
if (output.empty()) {
while(!input.empty()) {
output.push(input.top());
input.pop();
}
}
return output.top();
}
/** Returns whether the queue is empty. */
bool empty() {
return input.empty() && output.empty();
}
}
Be First to Comment